In this third post of the Undetermined Points and Systems of Linear Equations series, students shift their focus from identifying unknown coordinate points to solving linear equations algebraically. Building on earlier lessons that paired tactile graphing and Desmos exploration, this activity challenges students to use auditory graph feedback and digital tools to understand how a single equation can represent a line—and how solving that equation helps identify missing values. Whether working from an equation or interpreting a graph, students begin connecting algebraic reasoning with visual and spatial representations of linear relationships.
By this point, students should have solved linear equations with one variable using inverse operations. Another way to solve a linear equation with one variable is by graphing and solving a system of equations based on the given linear equation. You may notice that this is not so dissimilar to what you have done in Activities 1 and 2 in this set. To solve an equation with one variable, write a system using both sides of the equation. Then use the Audio Trace feature in Desmos to solve the system.
Note: Some screen readers have trouble reading math equations in this website. For a fully accessible version of this post, download the accessible Word document, Solving a Linear Equation.
Problem: Use a system of equations to solve 5x + 6 = -4.
Step 1: Write a system of equations. Set each side of the equation equal to y.
y = 5x + 6
y = -4
Step 2: Enter these equations in the expression list and graph in the standard viewing window.
Image 1:
Step 3: Audio trace either one of the two equations. Use the points of interest keys (k and i) to determine the intersection of the two equations.
Image 2:
Step 4: Create a point at the intersection using an ordered pair in expression 3 and label the point.
Image 3:
The solution is x = -2. You can check this by substituting – 2 into the original equation.
5x + 6 = -4
5(-2) + 6 = -4
-10 + 6 = -4
-4 = -4
True.
Problem: Use a system of equations to solve 3x + 12 = -5x – 18.
Step 1: Write a system of equations. Set each side of the equation equal to y.
y = 3x + 12
y = -5x – 18
Step 2: Enter these equations in the expression list and graph in the standard viewing window.
Image 4:
Step 3: Audio trace either one of the two equations. Use the points of interest keys (k and i) to determine the intersection of the two equations.
Image 5:
Step 4: Create a point at the intersection using an ordered pair in expression 3 and label the point.
Image 6:
The solution is x = -3.75. You can check this by substituting -3.75 into the original equation.
3x + 12 = -5x – 18
3(-3.75) + 12 = -5(-3.75) – 18
-11.25 + 12 = 18.75 – 18
.75 = .75
True.
In this activity set, we have graphed systems of equations on the pegboard and on the Desmos graphing calculator. We have determined unknown points on a line using navigation in the Audio Trace feature of Desmos, as well as by using a system of equation. Finally, we solved a linear equation using a system of equations. In the next activity set, we will practice inequalities and systems of inequalities.
Activity set 1, Graphing Concepts series:
Activity set 2, Graph Board to Desmos series:
Activity set 3, Linear Functions and Problem Solving series (y-intercept and slope) series:
Activity set 4, Undetermined points and systems of linear equations series:
Activity set 5: Inequalities and systems of inequalities series:
Additional math resources by TEAM Initiative:
Pegboard post:
This algebra post was created as part of the TEAM Initiative to assist Teachers of Students with Visual Impairments (TSVIs) in teaching students digital math tools and to use tactile resources to support digital concepts. Written by John Rose. If you would like more information about the TEAM Initiative, contact Leslie Thatcher at [email protected].
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